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今天就跟大家聊聊有关 Java8中怎么操作Stream 对集合，可能很多人都不太了解，为了让大家更加了解，小编给大家总结了以下内容，希望大家根据这篇文章可以有所收获。
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首先为了说明Stream对对象集合的操作，新建一个Student类（学生类）,覆写了equals()和hashCode()方法
public class Student {
private Long id;
private String name;
private int age;
private String address;
public Student() {}
public Student(Long id, String name, int age, String address) {
this.id = id;
this.name = name;
this.age = age;
this.address = address;
}
@Override
public String toString() {
return "Student{" +
"id=" + id +
", name='" + name + '\'' +
", age=" + age +
", address='" + address + '\'' +
'}';
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Student student = (Student) o;
return age == student.age &&
Objects.equals(id, student.id) &&
Objects.equals(name, student.name) &&
Objects.equals(address, student.address);
}
@Override
public int hashCode() {
return Objects.hash(id, name, age, address);
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address;
}
}public static void main(String [] args) {
Student s1 = new Student(1L, "肖战", 15, "浙江");
Student s2 = new Student(2L, "王一博", 15, "湖北");
Student s3 = new Student(3L, "杨紫", 17, "北京");
Student s4 = new Student(4L, "李现", 17, "浙江");
List students = new ArrayList<>();
students.add(s1);
students.add(s2);
students.add(s3);
students.add(s4);
List streamStudents = testFilter(students);
streamStudents.forEach(System.out::println);
}
/**
* 集合的筛选
* @param students
* @return
*/
private static List testFilter(List students) {
//筛选年龄大于15岁的学生
// return students.stream().filter(s -> s.getAge()>15).collect(Collectors.toList());
//筛选住在浙江省的学生
return students.stream().filter(s ->"浙江".equals(s.getAddress())).collect(Collectors.toList());
} 运行结果：
这里我们创建了四个学生，经过filter的筛选，筛选出地址是浙江的学生集合。
public static void main(String [] args) {
Student s1 = new Student(1L, "肖战", 15, "浙江");
Student s2 = new Student(2L, "王一博", 15, "湖北");
Student s3 = new Student(3L, "杨紫", 17, "北京");
Student s4 = new Student(4L, "李现", 17, "浙江");
List students = new ArrayList<>();
students.add(s1);
students.add(s2);
students.add(s3);
students.add(s4);
testMap(students);
}
/**
* 集合转换
* @param students
* @return
*/
private static void testMap(List students) {
//在地址前面加上部分信息，只获取地址输出
List addresses = students.stream().map(s ->"住址:"+s.getAddress()).collect(Collectors.toList());
addresses.forEach(a ->System.out.println(a));
} 运行结果
map就是将对应的元素按照给定的方法进行转换。
public static void main(String [] args) {
testDistinct1();
}
/**
* 集合去重（基本类型）
*/
private static void testDistinct1() {
//简单字符串的去重
List list = Arrays.asList("111","222","333","111","222");
list.stream().distinct().forEach(System.out::println);
} 运行结果：
public static void main(String [] args) {
testDistinct2();
}
/**
* 集合去重（引用对象）
*/
private static void testDistinct2() {
//引用对象的去重，引用对象要实现hashCode和equal方法，否则去重无效
Student s1 = new Student(1L, "肖战", 15, "浙江");
Student s2 = new Student(2L, "王一博", 15, "湖北");
Student s3 = new Student(3L, "杨紫", 17, "北京");
Student s4 = new Student(4L, "李现", 17, "浙江");
Student s5 = new Student(1L, "肖战", 15, "浙江");
List students = new ArrayList<>();
students.add(s1);
students.add(s2);
students.add(s3);
students.add(s4);
students.add(s5);
students.stream().distinct().forEach(System.out::println);
} 运行结果：
可以看出，两个重复的“肖战”同学进行了去重，这不仅因为使用了distinct()方法，而且因为Student对象重写了equals和hashCode()方法，否则去重是无效的。
public static void main(String [] args) {
testSort1();
}
/**
* 集合排序（默认排序）
*/
private static void testSort1() {
List list = Arrays.asList("333","222","111");
list.stream().sorted().forEach(System.out::println);
} 运行结果：
public static void main(String [] args) {
testSort2();
}
/**
* 集合排序（指定排序规则）
*/
private static void testSort2() {
Student s1 = new Student(1L, "肖战", 15, "浙江");
Student s2 = new Student(2L, "王一博", 15, "湖北");
Student s3 = new Student(3L, "杨紫", 17, "北京");
Student s4 = new Student(4L, "李现", 17, "浙江");
List students = new ArrayList<>();
students.add(s1);
students.add(s2);
students.add(s3);
students.add(s4);
students.stream()
.sorted((stu1,stu2) ->Long.compare(stu2.getId(), stu1.getId()))
.sorted((stu1,stu2) -> Integer.compare(stu2.getAge(),stu1.getAge()))
.forEach(System.out::println);
} 运行结果：
上面指定排序规则，先按照学生的id进行降序排序，再按照年龄进行降序排序
public static void main(String [] args) {
testLimit();
}
/**
* 集合limit，返回前几个元素
*/
private static void testLimit() {
List list = Arrays.asList("333","222","111");
list.stream().limit(2).forEach(System.out::println);
} 运行结果：
public static void main(String [] args) {
testSkip();
}
/**
* 集合skip，删除前n个元素
*/
private static void testSkip() {
List list = Arrays.asList("333","222","111");
list.stream().skip(2).forEach(System.out::println);
} 运行结果：
public static void main(String [] args) {
testReduce();
}
/**
* 集合reduce,将集合中每个元素聚合成一条数据
*/
private static void testReduce() {
List list = Arrays.asList("欢","迎","你");
String appendStr = list.stream().reduce("北京",(a,b) -> a+b);
System.out.println(appendStr);
} 运行结果：
public static void main(String [] args) {
testMin();
}
/**
* 求集合中元素的最小值
*/
private static void testMin() {
Student s1 = new Student(1L, "肖战", 14, "浙江");
Student s2 = new Student(2L, "王一博", 15, "湖北");
Student s3 = new Student(3L, "杨紫", 17, "北京");
Student s4 = new Student(4L, "李现", 17, "浙江");
List students = new ArrayList<>();
students.add(s1);
students.add(s2);
students.add(s3);
students.add(s4);
Student minS = students.stream().min((stu1,stu2) ->Integer.compare(stu1.getAge(),stu2.getAge())).get();
System.out.println(minS.toString());
} 运行结果：
上面是求所有学生中年龄最小的一个，max同理，求最大值。
public static void main(String [] args) {
testMatch();
}
private static void testMatch() {
Student s1 = new Student(1L, "肖战", 15, "浙江");
Student s2 = new Student(2L, "王一博", 15, "湖北");
Student s3 = new Student(3L, "杨紫", 17, "北京");
Student s4 = new Student(4L, "李现", 17, "浙江");
List students = new ArrayList<>();
students.add(s1);
students.add(s2);
students.add(s3);
students.add(s4);
Boolean anyMatch = students.stream().anyMatch(s ->"湖北".equals(s.getAddress()));
if (anyMatch) {
System.out.println("有湖北人");
}
Boolean allMatch = students.stream().allMatch(s -> s.getAge()>=15);
if (allMatch) {
System.out.println("所有学生都满15周岁");
}
Boolean noneMatch = students.stream().noneMatch(s -> "杨洋".equals(s.getName()));
if (noneMatch) {
System.out.println("没有叫杨洋的同学");
}
} 看完上述内容，你们对 Java8中怎么操作Stream 对集合有进一步的了解吗？如果还想了解更多知识或者相关内容，请关注创新互联行业资讯频道，感谢大家的支持。
