13518219792
对于像'Wed, 11 Apr 2012 09:37:05 +0800'的时间格式化可如下解：
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date='Wed, 11 Apr 2012 09:37:05 +0800'
dd=datetime.datetime.strptime(date,'%a, %d %b %Y %H:%M:%S %z')
dd.strftime('%Y-%m-%d %H:%M:%S')
Python格式化日期时间的函数为datetime.datetime.strftime()；由字符串转为日期型的函数为：datetime.datetime.strptime()，两个函数都涉及日期时间的格式化字符串，列举如下：
%a Abbreviated weekday name
%A Full weekday name
%b Abbreviated month name
%B Full month name
%c Date and time representation appropriate for locale
%d Day of month as decimal number (01 - 31)
%H Hour in 24-hour format (00 - 23)
%I Hour in 12-hour format (01 - 12)
%j Day of year as decimal number (001 - 366)
%m Month as decimal number (01 - 12)
%M Minute as decimal number (00 - 59)
%p Current locale's A.M./P.M. indicator for 12-hour clock
%S Second as decimal number (00 - 59)
%U Week of year as decimal number, with Sunday as first day of week (00 - 51)
%w Weekday as decimal number (0 - 6; Sunday is 0)
%W Week of year as decimal number, with Monday as first day of week (00 - 51)
%x Date representation for current locale
%X Time representation for current locale
%y Year without century, as decimal number (00 - 99)
%Y Year with century, as decimal number
%z, %Z Time-zone name or abbreviation; no characters if time zone is unknown
%% Percent sign
from datetime import datetime
import math
def last_xmonth(x):
now = datetime.now()
if x==0:
return now
else:
a = x%12 # 取余数 前a个月 限制0a12
b = math.ceil(x/12)+1 if x%12==0 else math.ceil(x/12) # 前b-1年
if xnow.month:
date1 = datetime.strftime(datetime(now.year-b+1,now.month-a,now.day),'%Y-%m-%d')
else :
date1 = datetime.strftime(datetime(now.year-b,now.month+12-a,now.day),'%Y-%m-%d')
return date1
time()函数可以获取当前时间戳；ctime()函数可以以一种易读的方式获取系统当前时间；gmtime()函数可获取当前0时区的struct_time格式的时间；localtime()函数可获取当前地区的struct_time格式的时间。
