网站建设资讯

NEWS

网站建设资讯

python实现数独游戏-创新互联

这篇文章主要介绍了python 实现数独游戏的方法,具有一定借鉴价值,需要的朋友可以参考下。如下资料是关于python 实现数独游戏的详细步骤内容。

在金门等地区,都构建了全面的区域性战略布局,加强发展的系统性、市场前瞻性、产品创新能力,以专注、极致的服务理念,为客户提供网站建设、成都做网站 网站设计制作定制网站设计,公司网站建设,企业网站建设,成都品牌网站建设,网络营销推广,成都外贸网站制作,金门网站建设费用合理。

一、数独问题的基本规则
规则一:同一行数字不同
规则二:同一列数字不同
规则三:同一宫数字不同

二、解决数独的策略
1,简单方法
第一步,在每个格子中按照基本规则MT4写入可能的结果
第二步,判断每个格子中结果的个数,如果结果唯一,则写入该数字。
第三步,返回步骤一,循环
停止的标志:填满所有格子,或格子中可能的结果最小数大于1。

2,中级方法
第一步,使用简单方法
第二步,在每一宫中,某个数字出现的次数只有一次,直接填入该数字
第三步,返回步骤一,循环
停止的标志:不在有数字填入

3,终极方法
第一步,使用中级方法
第二步,对每个位置的每个可能的答案进行假设,并推导矛盾,排除。
(1)在第一个位置上,填入第一个可能的答案
(2)使用中级方法,推导填入数字
(3)如果矛盾A出现,假设不成立,返回该位置,填入第二个答案。
如果矛盾B出现,假设暂时成立,进入下一位置,填入答案。
循环结束标志:填满数字并符合基本规则

三 代码如下

import pandas as pd
import numpy as np
shudu_data=pd.read_csv('data/shudu.csv')
data=shudu_data.copy()

def block(i,data):
ru3_1=data.iloc[0:3,0:3]
ru3_2=data.iloc[0:3,3:6]
ru3_3=data.iloc[0:3,6:]
ru3_4=data.iloc[3:6,0:3]
ru3_5=data.iloc[3:6,3:6]
ru3_6=data.iloc[3:6,6:]
ru3_7=data.iloc[6:,0:3]
ru3_8=data.iloc[6:,3:6]
ru3_9=data.iloc[6:,6:]


ru3_list=[ru3_1,ru3_2,ru3_3,ru3_4,ru3_5,ru3_6,ru3_7,ru3_8,ru3_9]

ru3=ru3_list[i] ru3=ru3.values.tolist() lis=[] for l in ru3:   lis+=l ru3=set(lis)-{0}

return ru3

def Block_dataframe(i,data):

ru3_1=pd.DataFrame(data=data.iloc[0:3,0:3],index=[0,1,2],columns=['0','1','2'])

ru3_2=pd.DataFrame(data=data.iloc[0:3,3:6],index=[0,1,2],columns=['3','4','5']) ru3_3=pd.DataFrame(data=data.iloc[0:3,6:],index=[0,1,2],columns=['6','7','8']) ru3_4=pd.DataFrame(data=data.iloc[3:6,0:3],index=[3,4,5],columns=['0','1','2']) ru3_5=pd.DataFrame(data=data.iloc[3:6,3:6],index=[3,4,5],columns=['3','4','5']) ru3_6=pd.DataFrame(data=data.iloc[3:6,6:],index=[3,4,5],columns=['6','7','8']) ru3_7=pd.DataFrame(data=data.iloc[6:,0:3],index=[6,7,8],columns=['0','1','2']) ru3_8=pd.DataFrame(data=data.iloc[6:,3:6],index=[6,7,8],columns=['3','4','5']) ru3_9=pd.DataFrame(data=data.iloc[6:,6:],index=[6,7,8],columns=['6','7','8']) ru3_list=[ru3_1,ru3_2,ru3_3,ru3_4,ru3_5,ru3_6,ru3_7,ru3_8,ru3_9] return ru3_list[i]

def jianyan(data):

flag=True
for ind in range(9):
   li_1=list(data.iloc[ind].values)
   li_=[]
   for li in li_1:
     if li!=0:
       li_.append(li)
   flag=(len(set(li_))==len(li_))
   if flag==False:
     return flag

for col in ['0','1','2','3','4','5','6','7','8']:
   li_2=list(data.iloc[:][col].values)
   li_=[]
   for li in li_2:
     if li!=0:
       li_.append(li)
   #print(set(li_))
   #print(li_)
   flag=(len(set(li_))==len(li_))
   if flag==False:
     return flag

for i in range(9):
   block_dataframe=Block_dataframe(i,data)
   li_3=block_dataframe.values.tolist()
   li_q=[]
   for li_ in li_3:
     li_q=li_q+li_  
   li_=[]
   for li in li_q:
     if li!=0:
       li_.append(li) 

   flag=(len(set(li_))==len(li_))
   if flag==False:
     return flag

return flag

def full(data):
for i in range(9):
for j in ['0','1','2','3','4','5','6','7','8']:
if data[j][i]==0:
return False
return True

def Block_num(index,colums,data):
if index in [0,1,2]:
if colums in ['0','1','2']:
block_num=0
elif colums in ['3','4','5']:
block_num=1
else:
block_num=2
if index in [3,4,5]:
if colums in ['0','1','2']:
block_num=3
elif colums in ['3','4','5']:
block_num=4
else:
block_num=5
if index in [6,7,8]:
if colums in ['0','1','2']:
block_num=6
elif colums in ['3','4','5']:
block_num=7
else:
block_num=8
return block_num

def len_re(index,colums,data):
result={1,2,3,4,5,6,7,8,9}
ru1=set(data.iloc[index])
ru2=set(data[colums])
if index in [0,1,2]:
if colums in ['0','1','2']:
ru3=block(0,data)
elif colums in ['3','4','5']:
ru3=block(1,data)
else:
ru3=block(2,data)
if index in [3,4,5]:
if colums in ['0','1','2']:
ru3=block(3,data)
elif colums in ['3','4','5']:
ru3=block(4,data)
else:
ru3=block(5,data)
if index in [6,7,8]:
if colums in ['0','1','2']:
ru3=block(6,data)
elif colums in ['3','4','5']:
ru3=block(7,data)
else:
ru3=block(8,data)
re=result-ru1-ru2-ru3-{0}

return re

class result():

def result(self,data):

  #计算每个位置上可能的结果,返回pos,ans   index=[0,1,2,3,4,5,6,7,8]   colums=['0','1','2','3','4','5','6','7','8']   pos=[]   ans=[]   for ind in index:     for col in colums:       if data[col][ind] ==0:         re=len_re(ind,col,data)         ans.append(list(re))         pos.append((ind,col))   return zip(pos,ans)

    def result_min_len(data):
R=result()
c=R.result(data)
reslut_len=[]
reslut_list=[]
try:
for pos,ans in c:
reslut_list.append(ans)
reslut_len.append(len(ans))
return min(reslut_len)

except:return False

class paichu():

def result(self,data):

  data_copy=data.copy()   #如果一个位置出现多个结果,循序试错,排除错误答案:   i=0   j=0   if result_min_len(data_copy)==0:     print('传入数据错误,计算中止')   else:     result_=result()     result_1=result_.result(data_copy)     pos_=[]     ans_1_b=[]     for pos,ans_list in result_1:       ind=pos[0]       col=pos[1]       ans_1_a=[]       for ans in ans_list:         j+=1         data_copy[col][ind]=ans         f=result_min_len(data_copy)         if f:           i+=1           ans_1_a.append(ans)         data_copy[col][ind]=0       ans_1_b.append(ans_1_a)       pos_.append((ind,col))     print('已经排除{}个数'.format(j-i))     return zip(pos_,ans_1_b)

class rule_1():

class rule_1():

def result(self,data):

  #如果ind=0,按行,ind=1,按列排除   ind=0   result_000=result()   answer_zip=result_000.result(data)   #rule1 如果n个相同的list在同一行/列,且元素数量等于list的个数,则该行其他待定cell可以排除list中所有元素   index_0=[]   index_1=[]   index_2=[]   index_3=[]   index_4=[]   index_5=[]   index_6=[]   index_7=[]   index_8=[]   ans_0=[]   ans_1=[]   ans_2=[]   ans_3=[]   ans_4=[]   ans_5=[]   ans_6=[]   ans_7=[]   ans_8=[]   for pos,ans in answer_zip:     if pos[ind]==0:       index_0.append(pos)       ans_0.append(ans)     elif pos[ind]==1:       index_1.append(pos)       ans_1.append(ans)     elif pos[ind]==2:       index_2.append(pos)       ans_2.append(ans)     elif pos[ind]==3:       index_3.append(pos)       ans_3.append(ans)     elif pos[ind]==4:       index_4.append(pos)       ans_4.append(ans)     elif pos[ind]==5:       index_5.append(pos)       ans_5.append(ans)     elif pos[ind]==6:       index_6.append(pos)       ans_6.append(ans)     elif pos[ind]==7:       index_7.append(pos)       ans_7.append(ans)     elif pos[ind]==8:       index_8.append(pos)       ans_8.append(ans)   index=[index_0,index_1,index_2,index_3,index_4,index_5,index_6,index_7,index_8]   ans=[ans_0,ans_1,ans_2,ans_3,ans_4,ans_5,ans_6,ans_7,ans_8]   ans_=[]   for ans_array in ans:     l2=[]     for i in ans_array:       l2.append(set(i))     for i in np.unique(l2):       if l2.count(i)==len(i):         for k,j in enumerate(l2):           if i!=j:             j=j-i             l2[k]=j     ans_.append(list(l2))   pos_=[]   for i in index:     pos_=pos_+i   ans_list=[]   for i in ans_:     ans_list=ans_list+i   ans_listn=[]   for i in ans_list:     ans_listn.append(list(i))   return zip(pos_,ans_listn)

class rule_2():

def result(self,data):
   #如果ind=0,按行,ind=1,按列排除
   ind=1
   result_000=result()
   answer_zip=result_000.result(data)

   #rule1 如果n个相同的list在同一行/列,且元素数量等于list的个数,则该行其他待定cell可以排除list中所有元素
   index_0=[]
   index_1=[]
   index_2=[]
   index_3=[]
   index_4=[]
   index_5=[]
   index_6=[]
   index_7=[]
   index_8=[] 

   ans_0=[]
   ans_1=[]
   ans_2=[]
   ans_3=[]
   ans_4=[]
   ans_5=[]
   ans_6=[]
   ans_7=[]
   ans_8=[]

   for pos,ans in answer_zip:
     if pos[ind]=='0':
       index_0.append(pos)
       ans_0.append(ans)
     elif pos[ind]=='1':
       index_1.append(pos)
       ans_1.append(ans)
     elif pos[ind]=='2':
       index_2.append(pos)
       ans_2.append(ans)
     elif pos[ind]=='3':
       index_3.append(pos)
       ans_3.append(ans)
     elif pos[ind]=='4':
       index_4.append(pos)
       ans_4.append(ans)
     elif pos[ind]=='5':
       index_5.append(pos)
       ans_5.append(ans)
     elif pos[ind]=='6':
       index_6.append(pos)
       ans_6.append(ans)
     elif pos[ind]=='7':
       index_7.append(pos)
       ans_7.append(ans)
     elif pos[ind]=='8':
       index_8.append(pos)
       ans_8.append(ans)

   index=[index_0,index_1,index_2,index_3,index_4,index_5,index_6,index_7,index_8]
   ans=[ans_0,ans_1,ans_2,ans_3,ans_4,ans_5,ans_6,ans_7,ans_8]

   ans_=[]
   for ans_array in ans:
     l2=[]
     for i in ans_array:
       l2.append(set(i))

     for i in np.unique(l2):
       if l2.count(i)==len(i):
         for k,j in enumerate(l2):
           if i!=j:
             j=j-i
             l2[k]=j
     ans_.append(list(l2))

   pos_=[]
   for i in index:
     pos_=pos_+i

   ans_list=[]
   for i in ans_:
     ans_list=ans_list+i
   ans_listn=[]
   for i in ans_list:
     ans_listn.append(list(i))
   return zip(pos_,ans_listn)

class rule_3():

def result(self,data):

   result_000=result()
   answer_zip=result_000.result(data)

   #rule3 如果n个相同的list在同一9宫格,且元素数量等于list的个数,则该行其他待定cell可以排除list中所有元素
   block_0=[]
   block_1=[]
   block_2=[]
   block_3=[]
   block_4=[]
   block_5=[]
   block_6=[]
   block_7=[]
   block_8=[] 

   index_0=[]
   index_1=[]
   index_2=[]
   index_3=[]
   index_4=[]
   index_5=[]
   index_6=[]
   index_7=[]
   index_8=[] 

   for pos,ans in answer_zip:
     index=pos[0]
     colums=pos[1]

     if index in [0,1,2]:
       if colums in ['0','1','2']:
         block_0.append(ans)
         index_0.append(pos)
       elif colums in ['3','4','5']:
         block_1.append(ans)
         index_1.append(pos)
       else:
         block_2.append(ans)
         index_2.append(pos)
     if index in [3,4,5]:
       if colums in ['0','1','2']:
         block_3.append(ans)
         index_3.append(pos)
       elif colums in ['3','4','5']:
         block_4.append(ans)
         index_4.append(pos)
       else:
         block_5.append(ans)
         index_5.append(pos)
     if index in [6,7,8]:
       if colums in ['0','1','2']:
         block_6.append(ans)
         index_6.append(pos)
       elif colums in ['3','4','5']:
         block_7.append(ans)
         index_7.append(pos)
       else:
         block_8.append(ans)
         index_8.append(pos)

   index=[index_0,index_1,index_2,index_3,index_4,index_5,index_6,index_7,index_8]    
   block=[block_0,block_1,block_2,block_3,block_4,block_5,block_6,block_7,block_8]

   ans_=[]  
   for index_array in block:
     l2=[]
     for i in index_array:
       l2.append(set(i))

     for i in np.unique(l2):
       if l2.count(i)==len(i):
         for k,j in enumerate(l2):
           if i!=j:
             j=j-i
             l2[k]=j   
     ans_.append(list(l2))

   pos_=[]
   for i in index:
     pos_=pos_+i

   ans_list=[]
   for i in ans_:
     ans_list=ans_list+i
   ans_listn=[]
   for i in ans_list:
     ans_listn.append(list(i))
   return zip(pos_,ans_listn)

class rule_():

def result(self,data):
   Rule_1=rule_1()
   Rule_2=rule_2()
   Rule_3=rule_3()

   result_dict_1={}
   for pos,ans in Rule_1.result(data):
     result_dict_1[pos]=set(ans)
   result_dict_2={}
   for pos,ans in Rule_2.result(data):
     result_dict_2[pos]=set(ans)  
   result_dict_3={}
   for pos,ans in Rule_3.result(data):
     result_dict_3[pos]=set(ans)

   #三本字典根据key值 取交集融合为最终结果
   key_list=result_dict_1.keys()
   result_dict={}
   for key in key_list:
     result_dict[key]=(result_dict_1[key])&(result_dict_2[key])&(result_dict_3[key])

   ans=[]
   pos=[]
   for key,value in result_dict.items():
     k=list(value)
     k.sort()
     ans.append(k)
     pos.append(key)

   return zip(pos,ans)

def fill_pinlv(result_zip,data):

#输入数据类型为zip

result_zip=result_zip result_list=list(result_zip) #print(result_zip) block_num_list=[] for tup in result_list:   pos=tup[0]   ans=tup[1]   block_num=Block_num(pos[0],pos[1],data)   block_num_list.append(block_num) #print(block_num_list) ind_list_0=[] ind_list_1=[] ind_list_2=[] ind_list_3=[] ind_list_4=[] ind_list_5=[] ind_list_6=[] ind_list_7=[] ind_list_8=[] ind_block_array=[] for ind,num in enumerate(block_num_list):   if num==0:     ind_list_0.append(ind)   if num==1:     ind_list_1.append(ind)          if num==2:     ind_list_2.append(ind)          if num==3:     ind_list_3.append(ind)   if num==4:     ind_list_4.append(ind)          if num==5:     ind_list_5.append(ind)      if num==6:     ind_list_6.append(ind)   if num==7:     ind_list_7.append(ind)          if num==8:     ind_list_8.append(ind)    ind_block_array=[ind_list_0,ind_list_1,ind_list_2,ind_list_3,ind_list_4,ind_list_5,ind_list_6,ind_list_7,ind_list_8] #print(ind_block_array) result_block_array=[] for ind_list in ind_block_array:   result_block_list=[]   for ind in ind_list:     result_block_list.append(result_list[ind])   result_block_array.append(result_block_list)   #print(result_block_array) #生成block_counter_array block_counter_array=[] for block_list in result_block_array:   counter_list=[]   for i in range(1,10):     counter=0     for pos,ans in block_list:       if i in ans:         counter+=1     counter_list.append(counter)   block_counter_array.append(counter_list) #print(block_counter_array) #更新数据data jishuqi=0 for block_index,block in enumerate(block_counter_array):   processing_num=0   processing_num_pos=False   for num,count in enumerate(block):     if count==1:       processing_num=num+1       for tup in result_list:         pos=tup[0]         ans=tup[1]         if block_index==Block_num(pos[0],pos[1],data):           #print(block_index)           if processing_num in ans:             #print(pos)             processing_num_pos=pos             jishuqi+=1             data[processing_num_pos[1]][processing_num_pos[0]]=processing_num             if jianyan(data)==False:               data[processing_num_pos[1]][processing_num_pos[0]]=0               return jishuqi return jishuqi

def fill_jilian(data):
jishuqi=0
for i in range(1,10):
index_list=[]
col_list=[]
block_dataframe=pd.DataFrame()
for block_num in range(9):
#print(block_num)
block_dataframe=Block_dataframe(block_num,data)
index_list=list(block_dataframe.index)
col_list=list(block_dataframe.columns)
if i not in block_dataframe.values:
#排除行 index
for ind in index_list:
for col in range(9):
if i==data.iloc[ind][col]:
index_list.remove(ind)
#排除列 col
for col in col_list:
for ind in range(9):
if i ==data[col][ind]:
col_list.remove(col)

 #排除有数的cell

    pos_list=[]     for ind in index_list:       for col in col_list:         pos=(ind,col)         pos_list.append(pos)     for pos in pos_list:       if data[pos[1]][pos[0]]!=0:         pos_list.remove(pos)     #print(pos_list)     #填入数字     if len(pos_list)==1:       pos=pos_list[0]       data[pos[1]][pos[0]]=i         jishuqi+=1 #print('已经填入{}个数字'.format(jishuqi)) return jishuqi

def fill(data,classname):
#print('执行中。。。')
data=data
if classname =='result':
cla=result()
elif classname=='paichu':
cla=paichu()
elif classname=='rule':
cla=rule
()

#如果位置上只有一种可能,就直接填入data

i=0 m=0 flag_1=True while(flag_1):   if result_min_len(data)==0:     #print('上一轮输入的数据有误')     flag_1=False     m=i   for pos,ans in cla.result(data):     #print(len(ans))     if len(ans)==1:       i+=1       ind=pos[0]       col=pos[1]       data[col][ind]=ans[0]       if jianyan(data)==False:         #print('填入数据出错,已停止填写')         flag_1=False         break         if m == i:     break        #如果位置上只有多种可能,就使用fill_jilian()填入data j=0 m=0 flag_2=True while(flag_2):   if result_min_len(data)==0:     #print('上一轮输入的数据有误')     flag_2=False   if jianyan(data)==False:     #print('填入数据出错,已停止填写')     flag_2=False   m=j   j=j+fill_pinlv(cla.result(data),data)   if m == j:     break

def labelinit(data):
R=rule
()
label_list=[]
for pos,ans in R.result(data):
label_list.append([pos,ans,[None]*len(ans)])
return label_list

def label_change_B(pos,ans,label_list):
#label_list_copy=label_list.copy()
for l in label_list:
if l[0]==pos:
for a in range(len(l[2])):
l[2][a]=False
if ans == l[1][a]:
l[2][a]=True
return

def label_change_A(pos,ans,label_list):
#label_list_copy=label_list.copy()
for l in label_list:
if l[0]==pos:
for a in range(len(l[2])):
l[2][a]=False
if ans == l[1][a]:
l[2][a]=False
return

def label_rechange(data,label_list):
try:
#更新label_list
for ind,l in enumerate(label_list):
if (None not in l[2]) and (True not in l[2]):
#清空最后一行
process_1=[None]*len(l[1])
#上一行True后移一个单位
process_2=label_list[ind-1][2]
index=process_2.index(True)+1
process_2.pop()
process_2.insert(0,False)
label_list[ind][2]=process_1
label_list[ind-1][2]=process_2
return True
except:
print('label_rechange 出错')
print('请确认输入数据正确!!!')
return False

def data_change(data,label_list):
#根据label_list更新数据data
try:
for l in label_list:
if True in l[2]:
pos=l[0]
ans=l[1]
marker=l[2]
data[pos[1]][pos[0]]=ans[marker.index(True)]
else:
print('data 按照label假设完成')
break
except:
print('data_change 出错')

def AB_test(data_copy):


flag=None

#AB判断(3种方向,1成功,2返回,3继续,) flag_1=jianyan(data_copy) flag_2=full(data_copy) flag_3=result_min_len(data) if flag_1==True:   if flag_2==True:     #1成功     print('C:成功找到结果')     print(data_copy)     flag='C'   if flag_2==False:     if flag_3==0:       #2返回       print('A:遍历下一个ans')       flag='A'       #label_change(pos,ans,result_label_list)     if flag_3>0:       #3继续       print('B:进入下一位置')       flag='B'       #label_change(pos,ans,result_label_list) if flag_1==False:   #2返回   print('A:遍历下一个ans')   flag='A'   #label_change(pos,ans,result_label_list) return flag

def jiashe(data,label_list_array,lunci):

data_copy=data.copy()

R=result() ans_list=label_list_array[lunci][1] pos=label_list_array[lunci][0] for ans in ans_list:   #假设   data_copy[pos[1]][pos[0]]=ans   #推导   fill(data_copy,'result')   fill(data_copy,'rule_')   fill(data_copy,'rule_')   label=AB_test(data_copy)   if label=='B':     #假设下一位置 重启假设函数     label_change_B(pos,ans,label_list_array)     return 'B'   elif label=='A':     #假设下一ans 遍历下一个ans     label_change_A(pos,ans,label_list_array)   elif label=='C':     #print('success')     return data_copy

def jie(data,label_list_array):
ind=0
for i in range(10):

 f_1=jiashe(data,label_list_array,ind)

  if type(f_1)==pd.core.frame.DataFrame:     return f_1   f_2=label_rechange(data,label_list_array)   data_change(data,label_list_array)   ind+=1   if f_2:     ind-=1     print('B:返回上一位置')   if f_2==False:     return False

  #print(label_list_array[0:5])

def main(data):
datacopy=data.copy()
fill(data,'result')
fill(data,'rule
')
label_list_array=label_init(data)
shudu_jie=jie(data,label_list_array)
print('原始数据')
print(data_copy)
print('结果是')
print(shudu_jie)

main(data)

看完这篇文章,你们学会python 实现数独游戏的方法了吗?如果还想学到更多技能或想了解更多相关内容,欢迎关注创新互联行业资讯频道,感谢各位的阅读。

另外有需要云服务器可以了解下创新互联cdcxhl.cn,海内外云服务器15元起步,三天无理由+7*72小时售后在线,公司持有idc许可证,提供“云服务器、裸金属服务器、高防服务器、香港服务器、美国服务器、虚拟主机、免备案服务器”等云主机租用服务以及企业上云的综合解决方案,具有“安全稳定、简单易用、服务可用性高、性价比高”等特点与优势,专为企业上云打造定制,能够满足用户丰富、多元化的应用场景需求。


当前标题:python实现数独游戏-创新互联
文章转载:http://njwzjz.com/article/dhddgi.html