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VB把二进制转化为十进制的方法：
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' 用途：将二进制转化为十进制 ' 输入：Bin(二进制数) ' 输入数据类型：String
' 输出：BIN_to_DEC(十进制数) ' 输出数据类型：Long
' 输入的最大数为1111111111111111111111111111111(31个1),输出最大数为2147483647
Public Function BIN_to_DEC(ByVal Bin As String) As Long Dim i As Long
For i = 1 To Len(Bin)
BIN_to_DEC = BIN_to_DEC * 2 + Val(Mid(Bin, i, 1)) Next i
End Function
比如输入：1010
输出就是：10
首先引入System.IO命名空间
Imports System.IO
然后使用文件流来读入数组：
Dim bytes() As Byte
Using fs As New FileStream(文件路径,FileMode.Open)
ReDim bytes(fs.Length-1)
fs.Read(bytes,0,fs.Length)
fs.Close()
End Using
这样bytes就是整个文件的所有字节了
从字节生成Image：
Dim img As Image = Image.FromStream(New MemoryStream(bytes))
img就是图片了
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim MyStream As New System.IO.MemoryStream
Me.PictureBox1.Image.Save(MyStream, System.Drawing.Imaging.ImageFormat.Jpeg)
Dim MyBytes(MyStream.Length) As Byte
MyStream.Read(MyBytes, 0, MyStream.Length)
MyStream.Close()
Dim strText As String
strText = BitConverter.ToString(MyBytes)
Me.TextBox1.Text = strText
End Sub
Option Explicit
Dim Jz As Integer, K As Boolean
Private Sub Command1_Click()
Pic.Cls
If K Then Jz = Val(Qtjz.Text)
If Pd(Text1.Text, Jz) Then Pic.Print "选择的进制与数不符": Exit Sub
If Jz = 0 Then Pic.Print "请先输入进制" Else Pic.Print Zh(Text1.Text, Jz)
End Sub
Private Sub Command2_Click()
End
End Sub
Private Sub Frame1_DragDrop(Source As Control, X As Single, Y As Single)
End Sub
Private Sub Option1_Click(Index As Integer)
K = False
Select Case Index
Case 0
Jz = 2
Case 1
Jz = 8
Case 2
Jz = 10
Case 3
Jz = 16
Case 4
K = True
Qtjz.Text = ""
Qtjz.SetFocus
End Select
If Index 4 Then Command1.SetFocus
End Sub
Private Sub Qtjz_Click()
Qtjz.Text = ""
End Sub
Private Sub Text1_Click()
Text1.Text = ""
End Sub
Private Function Zh(a As String, b As Integer) As Integer
Dim c As String, i, d As Integer
a = LCase(a)
For i = 1 To Len(a)
c = Mid(a, Len(a) + 1 - i, 1)
If Asc(c) 96 Then d = Asc(c) - 87 Else d = Val(c)
Zh = Zh + d * b ^ (i - 1)
Next i
End Function
Private Function Pd(a As String, b As Integer) As Boolean
Dim c As String, i, d As Integer
Pd = False
For i = 1 To Len(a)
c = Mid(a, Len(a) + 1 - i, 1)
If Asc(c) 96 Then d = Asc(c) - 87 Else d = Val(c)
If d b - 1 Then Pd = True: Exit Function
Next i
End Function
